A procedure is going to be run to give values for an ordered pair (

a,

b). The value of the first parameter,

a, is decided by a fair coin. The value of the second parameter,

b, is decided as follows: (i) if

a = 0, then

b = 0, and (ii) if

a = 1, then

b = 0 or

b = 1 (decided again by a fair coin). The procedure is run; to what degree ought you believe that the procedure output 0 for the first parameter?

The answer is obvious. So in what important respect does the procedure above differ from the sleeping beauty scenario (if at all)?

## 1 comment:

A procedure is going to be run to give values for an ordered pair (a,b). The value of the first parameter, a, is decided by a fair coin. The value of the second parameter, b, is also decided by a fair coin. The procedure is run; given that the pair (0,1) was not output, to what degree ought you believe that the procedure output 0 for the first parameter?

Why is this different?

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