A procedure is going to be run to give values for an ordered pair (
a,
b). The value of the first parameter,
a, is decided by a fair coin. The value of the second parameter,
b, is decided as follows: (i) if
a = 0, then
b = 0, and (ii) if
a = 1, then
b = 0 or
b = 1 (decided again by a fair coin). The procedure is run; to what degree ought you believe that the procedure output 0 for the first parameter?
The answer is obvious. So in what important respect does the procedure above differ from the sleeping beauty scenario (if at all)?
1 comment:
A procedure is going to be run to give values for an ordered pair (a,b). The value of the first parameter, a, is decided by a fair coin. The value of the second parameter, b, is also decided by a fair coin. The procedure is run; given that the pair (0,1) was not output, to what degree ought you believe that the procedure output 0 for the first parameter?
Why is this different?
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